Topic · Pre-Algebra

Scientific Notation

Some numbers in the real world are too big or too small to write out — the mass of the Earth, the size of an atom, the population of the planet. Scientific notation is the compact form scientists, engineers, and calculators all use: a single digit, some more digits after a point, times a power of ten.

What you'll leave with

  • The standard form $a \times 10^n$ with $1 \leq |a| < 10$.
  • Converting between standard form and ordinary decimal notation in both directions.
  • How to multiply and divide in scientific notation — combine the $a$'s, combine the exponents.
  • How to add and subtract — line up the exponents first.
  • What "significant figures" mean and why scientific notation makes them obvious.

1. Why we need it

Some numbers from the real world:

  • Speed of light: $299{,}792{,}458$ m/s.
  • Mass of the Sun: $1{,}989{,}000{,}000{,}000{,}000{,}000{,}000{,}000{,}000{,}000$ kg.
  • Diameter of a hydrogen atom: $0.000{,}000{,}000{,}053$ m.
  • Mass of an electron: $0.000{,}000{,}000{,}000{,}000{,}000{,}000{,}000{,}000{,}910{,}9$ kg.

Counting the zeros is unbearable, and a single miscount silently destroys the answer. Scientific notation fixes both problems by writing the number as a single small factor times a power of ten — exactly the powers-of-ten structure already at the heart of base-10 place value.

2. The standard form

A number is in scientific notation (or standard form) when it's written as

$$ a \times 10^n $$

where $a$ is a real number with $1 \leq |a| < 10$ — exactly one digit (other than zero) to the left of the decimal point — and $n$ is an integer (positive, negative, or zero).

Scientific notation

A number written in the form $a \times 10^n$ with $1 \leq |a| < 10$ and integer $n$. The coefficient $a$ holds the digits; the exponent $n$ holds the order of magnitude.

The numbers from the previous section, in standard form:

QuantityDecimalScientific notation
Speed of light$299{,}792{,}458$$2.99792458 \times 10^8$ m/s
Mass of the Sun$1.989 \times 10^{30}$$1.989 \times 10^{30}$ kg
Atom diameter$0.000{,}000{,}000{,}053$$5.3 \times 10^{-11}$ m
Electron mass$\approx 9.109 \times 10^{-31}$$9.109 \times 10^{-31}$ kg

The whole point: the exponent $n$ counts orders of magnitude at a glance. The Sun is $10^{30}$ kg; an electron is $10^{-31}$ kg; the ratio is $\sim 10^{61}$ — a number you can compute mentally in scientific notation but would struggle with in expanded form.

3. Converting to and from standard form

Decimal to scientific notation

Count how many places you'd have to move the decimal point to land between the first digit and the rest. That count is the exponent — positive if you moved left, negative if right.

  • $45{,}300{,}000$ — move the point $7$ places left: $4.53 \times 10^7$.
  • $0.000{,}042$ — move the point $5$ places right: $4.2 \times 10^{-5}$.
  • $8.7$ — already in standard form: $8.7 \times 10^0$.

Scientific notation to decimal

Move the decimal point of $a$ by $|n|$ places: right if $n$ is positive, left if $n$ is negative.

  • $3.6 \times 10^4$ — move $4$ places right: $36{,}000$.
  • $2.5 \times 10^{-3}$ — move $3$ places left: $0.0025$.
The shortcut

Positive exponent → big number → move the point right. Negative exponent → small number → move the point left. The exponent always tells you the direction and the magnitude of the move.

4. Multiplying and dividing

This is where scientific notation earns its keep. To multiply two numbers in scientific notation, multiply the coefficients and add the exponents:

$$ (a \times 10^m) \cdot (b \times 10^n) = (a \cdot b) \times 10^{m+n}. $$

Example:

$$ (3 \times 10^4) \cdot (2 \times 10^5) = 6 \times 10^9. $$

Division — divide the coefficients, subtract the exponents:

$$ \frac{a \times 10^m}{b \times 10^n} = \frac{a}{b} \times 10^{m-n}. $$ $$ \frac{6 \times 10^8}{2 \times 10^3} = 3 \times 10^5. $$

If the multiplication of the coefficients pushes the result outside $[1, 10)$, you have to re-normalize. For example $(5 \times 10^3) \cdot (4 \times 10^2) = 20 \times 10^5 = 2 \times 10^6$ — shift one factor of $10$ from the coefficient into the exponent.

5. Adding and subtracting

Addition is awkward in scientific notation because the exponents don't combine the way they do in multiplication. To add or subtract, both numbers must first be expressed with the same power of ten — then you add or subtract the coefficients.

$$ (3.2 \times 10^4) + (4.1 \times 10^3). $$

Convert the second so that it shares the exponent of the first: $4.1 \times 10^3 = 0.41 \times 10^4$. Now the powers match:

$$ 3.2 \times 10^4 + 0.41 \times 10^4 = 3.61 \times 10^4. $$

The same trick works for subtraction. The principle is identical to adding fractions: you can't add until the denominators (here, the powers of $10$) match.

This is why orders of magnitude dominate

Adding a number in $10^4$ to one in $10^8$ leaves the small number essentially invisible — $3 \times 10^4$ added to $5 \times 10^8$ is $5.00003 \times 10^8$. The smaller term is four orders of magnitude beneath the rounding noise of the larger. In physics, this is often used to justify ignoring "small" terms entirely.

6. Significant figures

Scientific notation pairs naturally with the concept of significant figures — the digits in a measurement that actually carry information.

The number $0.00420$ has three significant figures (the leading zeros are placeholders, but the trailing zero after the $42$ is a meaningful digit — it's signalling that the measurement was made to the nearest hundredth of a milliunit, not just the nearest tenth). The number $4200$ is ambiguous — is the $00$ measured precisely, or just trailing? Scientific notation removes the ambiguity:

  • $4.2 \times 10^3$ — two significant figures.
  • $4.20 \times 10^3$ — three significant figures.
  • $4.200 \times 10^3$ — four significant figures.

In scientific notation, every digit in the coefficient is significant by construction. This is one reason scientists use it: it makes precision unambiguous.

The standard convention for results from a calculation: a final answer should have no more significant figures than the least-precise input. Multiplying a $3$-sig-fig number by a $5$-sig-fig number gives a $3$-sig-fig result — the extra precision is illusory.

7. Playground: convert and compute

Slide the coefficient $a$ and the exponent $n$. The same number is shown three ways: scientific form, the full written-out decimal, and a comparison against five real-world quantities so you can feel what each order of magnitude actually means.

6.02 × 1023
coefficient 6.02  ·  exponent 23
6.02
23
Written out in decimal
602,000,000,000,000,000,000,000
Compared to real-world quantities
QuantityValueOrder (n)
Avogadro's number6.022 × 102323
Earth's mass (kg)5.97 × 102424
Age of the universe (s)4.4 × 101717
Proton mass (kg)1.67 × 10-27-27
Atom diameter (m)~1 × 10-10-10
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Try it

Drag $n$ down to $-10$ and you're at the size of an atom. Up to $23$ and you're counting particles in a mole. Up to $24$ and you're weighing the Earth. Each step of $n$ multiplies the actual quantity by $10$ — a deceptively quiet motion of the slider, an enormous change in the thing being described.

8. Common pitfalls

Coefficient outside $[1, 10)$

$23 \times 10^4$ is correct arithmetic but not standard form, because $23 > 10$. Re-normalize: $23 \times 10^4 = 2.3 \times 10^5$. Similarly, $0.5 \times 10^3$ should be $5 \times 10^2$.

Sign of the exponent for small numbers

$0.0042$ is $4.2 \times 10^{-3}$, not $4.2 \times 10^3$. Numbers between $0$ and $1$ have negative exponents in scientific notation. Whenever the original number is less than $1$, the exponent is negative; the more zeros after the decimal point, the more negative.

Forgetting to match exponents before adding

$3 \times 10^4 + 2 \times 10^3 \neq 5 \times 10^7$, and it's not $5 \times 10^4$ either. Convert one number so the exponents match: $3 \times 10^4 + 0.2 \times 10^4 = 3.2 \times 10^4$. Only multiplication and division "combine the exponents directly."

Overclaiming significant figures

If your inputs were $3.2 \times 10^4$ and $4.1 \times 10^3$, the answer shouldn't be reported as $3.61000 \times 10^4$. The extra zeros suggest a precision you don't have. Stick to the number of sig figs the worst-measured input justifies.

9. Worked examples

Example 1 · Convert $0.00045$ to scientific notation

Move the decimal point right until exactly one nonzero digit sits to the left of it. Here that's $4$ places: $4.5$. Since we moved right, the exponent is negative:

$$ 0.00045 = 4.5 \times 10^{-4}. $$
Example 2 · Convert $7.8 \times 10^6$ to ordinary decimal

Positive exponent of $6$: move the point $6$ places right. Pad with zeros as needed:

$$ 7.8 \times 10^6 = 7{,}800{,}000. $$
Example 3 · $(3 \times 10^4)(2 \times 10^5)$

Multiply coefficients; add exponents:

$$ (3 \times 10^4)(2 \times 10^5) = 6 \times 10^{9}. $$

The coefficient $6$ is already in $[1, 10)$, so no re-normalization needed.

Example 4 · $\dfrac{4.8 \times 10^9}{1.6 \times 10^3}$

Divide coefficients; subtract exponents:

$$ \frac{4.8}{1.6} \times 10^{9 - 3} = 3 \times 10^6. $$
Example 5 · $(3.2 \times 10^4) + (4.1 \times 10^3)$

The exponents don't match. Rewrite the second number using $10^4$:

$$ 4.1 \times 10^3 = 0.41 \times 10^4. $$

Now add:

$$ 3.2 \times 10^4 + 0.41 \times 10^4 = 3.61 \times 10^4. $$

Sources & further reading

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